Have you ever spent hours staring at your screen, wondering why your Java program crashes for no obvious reason? From NullPointerException to subtle logic flaws hidden deep in your loops or conditions, debugging Java code can quickly become a frustrating guessing game. However, many of these issues are surprisingly common and often avoidable with the right habits and tools. In this article, we’ll explore 8 Java debugging common mistakes and show you practical ways to avoid them. Let’s get started!
One of the most frequent runtime errors in Java is the NullPointerException (NPE). An NPE occurs when code attempts to call a method or access a field on a reference that is null. In other words, the program expects an object, but finds null and cannot proceed with the operation. This typically causes the program to crash with an error that points to the line of code that is causing the issue.
Consider the following code, where a string is not initialised:
In this snippet, the message is null, so calling message.length() will throw a NullPointerException at runtime.
The primary way to avoid NPEs is to check for null before dereferencing objects. Defensive coding practices include using conditional checks, utilizing Java 8+ Optional to wrap potentially null values, or ensuring that methods never return null when an empty result can be used as an alternative. For example, if a method might not find a result, it could return an empty list or an Optional rather than null.
Here's a safer version that checks for null and uses a fallback:
An ArrayIndexOutOfBoundsException occurs when code attempts to access an array index outside the valid range (0 to length-1). This often results from off-by-one errors, classic mistakes where loops run one time too many or too few. In Java’s zero-based indexing, such bugs usually stem from incorrect loop conditions, like using <= instead of <, or miscalculating start/end indices, leading to attempts like array[array.length], which is invalid.
For example, in the code below, the loop runs one iteration too many, causing an out-of-bounds access:
When possible, use idiomatic loops that avoid explicit index management. For example, use Java’s enhanced for-loop (for (int num : numbers) { ... }) or streams, which handle bounds internally. If manual indexing is needed, double-check the logic for off-by-one issues. For instance, if you’re iterating from 0 to N-1 inclusive, your loop condition should be i < N, not i <= N. Additionally, when accessing arrays or list elements based on some calculation, it’s wise to assert or check that the index is within a valid range before use.
Here is a correct version of the loop above:
An infinite loop can be one of the most frustrating bugs in programming because it doesn't show an error. Instead, the program suddenly freezes or becomes unresponsive, making it difficult to determine what went wrong. You might see the app “doing nothing,” but behind the scenes, it's often stuck in a loop, consuming CPU endlessly.
Infinite loops are usually caused by mistakes in loop logic. Common causes include:
Here's a typical mistake:
This code will run forever because the condition i > 0 always remains true, and the loop variable i is never updated.
No matter if you're using a for, while, or do-while loop, it's important to ensure that the loop condition will eventually evaluate to false. This can be achieved by correctly updating loop variables or relying on external signals that are certain to change. Here are some practical tips to help you avoid getting stuck in an endless loop:
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A ClassCastException occurs at runtime when you try to cast an object to a class it doesn't actually belong to. This usually means the code made a wrong assumption about the object's actual type. For example:
This code will cause a ClassCastException because it tries to cast the string "Hello" to an Integer. When the program runs, the JVM will throw an error like this:
In Java, type casting is checked at runtime, and if an object isn't an instance of the class you're casting to, the program will crash. This often happens when:
Avoiding ClassCastException comes down to writing type-safe, well-structured code and making smart use of Java’s type system. Here's how you can prevent this error and make your code cleaner in the process:
✅ Use generics to enforce type safety – When you declare a collection with a specific type (e.g., List<String> or List<Integer>), the compiler ensures only objects of that type can be added. Because the compiler enforces type checks, you’ll catch type mismatches before they cause runtime crashes.
✅ Use instanceof when you must cast – Sometimes you have to work with APIs or legacy code that return Object or untyped values. In these cases, always check the type first to prevent your program from crashing when the object isn’t what you expected.
✅ Be cautious with unchecked casts and wildcards – Generics don’t completely eliminate the need for casting, especially when working with wildcard types (List<?>, List<? extends T>). Use extra caution when dealing with these cases:
Avoid unchecked casts unless you're absolutely sure of the type. When in doubt, restructure your code to make the type relationships more explicit.
✅ Design for type safety from the start – If you're finding yourself needing to mix types in a single collection, consider redesigning your data structure. Here are a few safer alternatives:
Converting strings to numbers often leads to a NumberFormatException, an error thrown when a string can’t be converted into a numeric type, such as int or double. Some common causes include:
For example:
The string "abc42" isn’t a valid number because of the letters. Running this code would throw an error like:
Always validate your input before attempting to parse it. Here are some practical strategies:
In many languages, == compares values. In Java, it compares values when working with primitive types, such as int, char, or boolean. But when you compare objects (like Strings), == checks if both variables point to the same object, not if their contents are the same.
For example:
This will output “They are not equal (==)” even though s1 and s2 contain the same text "Java". That’s because s1 == s2 is comparing memory references, and new String("Java") creates two distinct objects. In contrast, s1.equals(s2) would return true in this case because String.equals is overridden to compare the sequence of characters.
Use .equals() when comparing the contents of objects, especially Strings. Save == for comparing primitives (like int or boolean) or checking if an object is null. If you're working with custom classes, override equals() (and hashCode()) to define what "equal" means in your context.
Remember, == checks if two references point to the same object, not if the objects are logically the same. The compiler won’t catch this mistake, so rely on code reviews or static analysis tools to spot incorrect usage of == with objects.
This kind of subtle bug can silently break your logic and slip past compilers. Zencoder’s Code Review Agent provides targeted reviews at the file, function, or even single-line level. It delivers clear, actionable feedback that helps you catch logic flaws early and enforce consistency across your codebase.
A memory leak in Java doesn’t mean memory is permanently lost, thanks to garbage collection. Instead, it means your program is unintentionally holding references to objects it no longer needs. This prevents the garbage collector from cleaning them up, causing your app’s memory usage to grow.
Memory leaks can happen for various reasons:
Here are some tips to help you prevent memory leaks:
A resource leak occurs when your program opens a resource, such as a file, network socket, or database connection, but fails to close it when it's no longer needed. This can eventually exhaust system resources, such as open file handles or database connections. While Java’s garbage collector automatically reclaims memory, it doesn’t close external resources. You have to do that manually. Common mistakes include forgetting to call close() on a file or database connection, especially when an exception occurs. If resources remain open, it can lead to:
Always close your resources. The modern way is to use the try-with-resources statement (available since Java 7), which automatically closes any object that implements AutoCloseable when the block exits, even if exceptions occur. For example:
This eliminates the risk of forgetting to close resources and is cleaner than a manual finally block. If you are on Java 6 or earlier (or working with objects that aren’t AutoCloseable), use a finally block to close resources explicitly.
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